How to get current route

Angular RC4:

You can import Router from @angular/router

Then inject it:

constructor(private router: Router ) {

}

Then call it’s URL parameter:

console.log(this.router.url); //  /routename

Inject Location to your component and read location.path();
You need to add ROUTER_DIRECTIVES somewhere so Angular can resolve Location. You need to add import: [RouterModule] to the module.

Update

In the V3 (RC.3) router you can inject ActivatedRoute and access more details using its snapshot property.

constructor(private route:ActivatedRoute) {
  console.log(route);
}

or

constructor(private router:Router) {
  router.events.subscribe(...);
}

See also Angular 2 router event listener

Use this

import { Router, NavigationEnd } from '@angular/router';

constructor(private router: Router) {
    router.events.filter(event => event instanceof NavigationEnd)
        .subscribe(event => {
            console.log(event);
        });
}

And in main.ts import

import 'rxjs/add/operator/filter';

EDIT

Modern way

import {filter} from 'rxjs/operators';

router.events.pipe(
    filter(event => event instanceof NavigationEnd)
)
    .subscribe(event => {
        console.log(event);
    });

For those who are still looking for this. On Angular 2.x there are a few ways of doing it.

constructor(private router: Router, private activatedRoute: ActivatedRoute){

   // string path from root to current route. i.e /Root/CurrentRoute
   router.url 

    // just the fragment of the current route. i.e. CurrentRoute
   activatedRoute.url.value[0].path

    // same as above with urlSegment[]
   activatedRoute.url.subscribe((url: urlSegment[])=> console.log(url[0].path))

   // same as above
   activatedRoute.snapshot.url[0].path

   // the url fragment from the parent route i.e. Root
   // since the parent is an ActivatedRoute object, you can get the same using 
   activatedRoute.parent.url.value[0].path
}

References:

1. https://angular.io/docs/ts/latest/api/router/index/ActivatedRoute-interface.html
2. https://angular.io/docs/ts/latest/api/router/index/Router-class.html
3. https://angular.io/docs/ts/latest/guide/router.html

for new router >= RC.3

Best and a simple way to do this is!

import { Router } from '@angular/router';
constructor(router: Router) { 
      router.events.subscribe((url:any) => console.log(url));
      console.log(router.url);  // to print only path eg:"/login"
}

To get the route segments:

import { ActivatedRoute, UrlSegment } from '@angular/router';

constructor( route: ActivatedRoute) {}

getRoutes() { const segments: UrlSegment[] = this.route.snapshot.url; }

import { Router } from '@angular/router';
constructor(router: Router) { 
      console.log(router.routerState.snapshot.url);
}

To reliably get the full current route you can use this

this.router.events.subscribe(
  (event: any) => {
    if (event instanceof NavigationEnd) {
      console.log('this.router.url', this.router.url);
    }
  }
);

You can try with

import { Router, ActivatedRoute} from '@angular/router';    

constructor(private router: Router, private activatedRoute:ActivatedRoute) {
console.log(activatedRoute.snapshot.url)  // array of states
console.log(activatedRoute.snapshot.url[0].path) }

Alternative ways

router.location.path();   this works only in browser console. 

window.location.pathname which gives the path name.

The native window object works fine as well

console.log('URL:' + window.location.href);
console.log('Path:' + window.location.pathname);
console.log('Host:' + window.location.host);
console.log('Hostname:' + window.location.hostname);
console.log('Origin:' + window.location.origin);
console.log('Port:' + window.location.port);
console.log('Search String:' + window.location.search);

NOTE: DO NOT USE THIS IN SERVER SIDE RENDERING

I had the same problem using

this.router.url

I get the current route with query params. A workaround I did was using this instead:

this.router.url.split('?')[0]

Not a really nice solution, but helpful.

short version if you have Router imported then you can simply use some thing like

this.router.url === “/search”

else do the following

1) Import the router

import { Router } from '@angular/router';

2) Declare its entry in constructor

constructor(private router: Router) { }

3) Use its value in your function

yourFunction(){
    if(this.router.url === "/search"){
        //some logic
    }
}

@victor answer helped me, this is the same answer as him but with a little detail, as it might help someone

import { Router, NavigationEnd } from "@angular/router";

constructor(private router: Router) {
  // Detect current route
  router.events.subscribe(val => {
    if (val instanceof NavigationEnd) {
      console.log(val.url);
    }
});

This applies if you are using it with an authguard

this.router.events.subscribe(event => {
        if(event instanceof NavigationStart){
            console.log('this is what your looking for ', event.url);  
         }
       } 
   );

With angular 2.2.1 (in an angular2-webpack-starter based project) works this:

export class AppComponent {
  subscription: Subscription;
  activeUrl: string;

  constructor(public appState: AppState,
              private router: Router) {
    console.log('[app] constructor AppComponent');
  }

  ngOnInit() {
    console.log('[app] ngOnInit');
    let _this = this;
    this.subscription = this.router.events.subscribe(function (s) {
      if (s instanceof NavigationEnd) {
        _this.activeUrl = s.urlAfterRedirects;
      }
    });
  }

  ngOnDestroy() {
    console.log('[app] ngOnDestroy: ');
    this.subscription.unsubscribe();
  }
}

In AppComponent’s template you can use e.g. {{activeUrl}}.

This solution is inspired by RouterLinkActive’s code.

to get current router in angular 8 just do this

import {ActivatedRoute} from '@angular/router';

then inject it in constructor like

constructor(private route: ActivatedRoute){}

if you want get current route then use this route.url

if you have multiply name route like /home/pages/list and you wanna access individual then you can access each of like this route.url.value[0].path

value[0] will give home, value[1] will give you pages and value[2] will give you list

An easier way if you can’t access router.url (for instance if you used skipLocationChange) you can use the following :

import { Location } from '@angular/common';    
constructor(private readonly location: Location) {}
    
ngOnInit(): void {
  console.log(this.location.path());
}

WAY 1: Using Angular: this.router.url

import { Component } from '@angular/core';

// Step 1: import the router 
import { Router } from '@angular/router';

@Component({
    template: 'The href is: {{href}}'
    /*
    Other component settings
    */
})
export class Component {
    public href: string = "";

    //Step 2: Declare the same in the constructure.
    constructor(private router: Router) {}

    ngOnInit() {
        this.href = this.router.url;
        // Do comparision here.....
        ///////////////////////////
        console.log(this.router.url);
    }
}

WAY 2 Window.location as we do in the Javascript, If you don’t want to use the router

this.href= window.location.href;

You can use in the .ts file

import { Route, Router, NavigationStart } from '@angular/router';

constructor(private router: Router) {}

this.router.events.subscribe(value => {
      if (value instanceof NavigationStart) {
        console.log(value) // your current route
      }
    });

In Angular2 Rc1 you can inject a RouteSegment and then pass it into the .navigate() method:

constructor(private router:Router,private segment:RouteSegment) {}

ngOnInit() {
  this.router.navigate(["explore"],this.segment)
}

angular 2 rc2

router.urlTree.contains(router.createUrlTree(['/home']))

Here is what is working for me in Angular 2.3.1.

location: any;

constructor(private _router: Router) { 

      _router.events.subscribe((data:any) => { this.location = data.url; });

      console.warn(this.location);  // This should print only path e.g. "/home"
}

The data is an object and we need the url property contained in that object. So we capture that value in a variable and we can use that variable in our HTML page as well. For example, I want to show a div only when user is on Home page. In this case, my router url value will be /home. So I can write a div in the following way:

<div *ngIf="location == '/home'">
This is content for the home page.
</div>

You can use ActivatedRoute to get the current router

Original Answer (for RC version)

I found a solution on AngularJS Google Group and it’s so easy!

ngOnInit() {
  this.router.subscribe((url) => console.log(url));
}

Here’s the original answer

https://groups.google.com/d/msg/angular/wn1h0JPrF48/zl1sHJxbCQAJ

simplest way

import { Router } from '@angular/router';
constructor(router: Router) { 
      router.events.subscribe((url:any) => console.log(url));
      console.log(router.url);  <---------- to get only path eg:"/signUp"
}

For your purposes you can use this.activatedRoute.pathFromRoot.

import {ActivatedRoute} from "@angular/router";
constructor(public activatedRoute: ActivatedRoute){

}

With the help of pathFromRoot you can get the list of parent urls and check if the needed part of the URL matches your condition.

For additional information please check this article http://blog.2muchcoffee.com/getting-current-state-in-angular2-router/
or install ng2-router-helper from npm

npm install ng2-router-helper

this is simple, in angular 2 you only need to import the Router library like this:

import { Router } from '@angular/router';

Then in the constructor of the component or service you must instantiate it like this:

constructor(private _router: Router) {}

Then in any part of the code, either in a function, method, construct, whatever:

      this._router.events
        .subscribe(
            (url:any) => {
                let _ruta = "";
                url.url.split("https://stackoverflow.com/").forEach(element => {
                    if(element!=="" && _ruta==="")
                        _ruta="https://stackoverflow.com/"+element;  
                });
                console.log("route: "+_ruta); //<<<---- Root path
                console.log("to URL:"+url.url); //<<<---- Destination URL                    
                console.log("from URL:"+this._router.url);//<<<---- Current URL
            }); 

To find the parent of the current route, you can obtain the UrlTree from the router, using relative routes:

var tree:UrlTree = router.createUrlTree(['../'], {relativeTo: route});

Then to get the segments of the primary outlet:

tree.root.children[PRIMARY_OUTLET].segments;

As of now, I’m getting my path as follows –

this.router.url.subscribe(value => {
    // you may print value to see the actual object
    // console.log(JSON.stringify(value));
    this.isPreview = value[0].path === 'preview';
})

Where, router is an instance of ActivatedRoute